6a^2+10a=136

Solution for 6a^2+10a=136 equation:

6a^2+10a=136

We move all terms to the left:

6a^2+10a-(136)=0

a = 6; b = 10; c = -136;
Δ = b2-4ac
Δ = 102-4·6·(-136)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-58}{2*6}=\frac{-68}{12}
=-5+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+58}{2*6}=\frac{48}{12}
=4
$